!**********************************************************************
!   pi3f90.f - compute pi by integrating f(x) = 4/(1 + x**2)     
!
!  (C) 2001 by Argonne National Laboratory.
!      See COPYRIGHT in top-level directory.
!     
!   Each node: 
!    1) receives the number of rectangles used in the approximation.
!    2) calculates the areas of it's rectangles.
!    3) Synchronizes for a global summation.
!   Node 0 prints the result.
!
!  Variables:
!
!    pi  the calculated result
!    n   number of points of integration.  
!    x           midpoint of each rectangle's interval
!    f           function to integrate
!    sum,pi      area of rectangles
!    tmp         temporary scratch space for global summation
!    i           do loop index
!****************************************************************************
program main

 use mpi

 double precision  PI25DT
 parameter        (PI25DT = 3.141592653589793238462643d0)

 double precision  mypi, pi, h, sum, x, f, a
 integer n, myid, numprocs, i, rc
!                                 function to integrate
 f(a) = 4.d0 / (1.d0 + a*a)
 
 call MPI_INIT( ierr )
 call MPI_COMM_RANK( MPI_COMM_WORLD, myid, ierr )
 call MPI_COMM_SIZE( MPI_COMM_WORLD, numprocs, ierr )
 print *, 'Process ', myid, ' of ', numprocs, ' is alive'
 
 sizetype   = 1
 sumtype    = 2
 
 do 
    if ( myid .eq. 0 ) then
       write(6,98)
 98    format('Enter the number of intervals: (0 quits)')
       read(5,99) n
 99    format(i10)
    endif
      
    call MPI_BCAST(n,1,MPI_INTEGER,0,MPI_COMM_WORLD,ierr)

!                                 check for quit signal
    if ( n .le. 0 ) exit

!                                 calculate the interval size
    h = 1.0d0/n
 
    sum  = 0.0d0
    do i = myid+1, n, numprocs
       x = h * (dble(i) - 0.5d0)
       sum = sum + f(x)
    enddo
    mypi = h * sum

!                                 collect all the partial sums
    call MPI_REDUCE(mypi,pi,1,MPI_DOUBLE_PRECISION,MPI_SUM,0, &
                    MPI_COMM_WORLD,ierr)

!                                 node 0 prints the answer.
    if (myid .eq. 0) then
        write(6, 97) pi, abs(pi - PI25DT)
 97     format('  pi is approximately: ', F18.16, &
               '  Error is: ', F18.16)
    endif

 enddo

 call MPI_FINALIZE(rc)
 stop
end