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/* -*- Mode: C; c-basic-offset:4 ; indent-tabs-mode:nil ; -*- */
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/*
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* (C) 2001 by Argonne National Laboratory.
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* See COPYRIGHT in top-level directory.
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*/
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#include "mpi.h"
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#include <stdio.h>
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#include "mpitest.h"
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#define MAX_PROCESSES 10
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int main(int argc, char **argv)
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{
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int rank, size, i, j;
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int table[MAX_PROCESSES][MAX_PROCESSES];
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int errors = 0;
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int participants;
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int displs[MAX_PROCESSES];
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int recv_counts[MAX_PROCESSES];
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MTest_Init(&argc, &argv);
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MPI_Comm_rank(MPI_COMM_WORLD, &rank;;
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MPI_Comm_size(MPI_COMM_WORLD, &size);
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/* A maximum of MAX_PROCESSES processes can participate */
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if (size > MAX_PROCESSES)
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participants = MAX_PROCESSES;
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else
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participants = size;
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/* while (MAX_PROCESSES % participants) participants--; */
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if (MAX_PROCESSES % participants) {
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fprintf(stderr, "Number of processors must divide %d\n", MAX_PROCESSES);
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MPI_Abort(MPI_COMM_WORLD, 1);
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}
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if ((rank < participants)) {
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/* Determine what rows are my responsibility */
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int block_size = MAX_PROCESSES / participants;
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int begin_row = rank * block_size;
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int end_row = (rank + 1) * block_size;
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int send_count = block_size * MAX_PROCESSES;
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/* Fill in the displacements and recv_counts */
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for (i = 0; i < participants; i++) {
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displs[i] = i * block_size * MAX_PROCESSES;
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recv_counts[i] = send_count;
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}
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/* Paint my rows my color */
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for (i = begin_row; i < end_row; i++)
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for (j = 0; j < MAX_PROCESSES; j++)
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table[i][j] = rank + 10;
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/* Gather everybody's result together - sort of like an */
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/* inefficient allgather */
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for (i = 0; i < participants; i++) {
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void *sendbuf = (i == rank ? MPI_IN_PLACE : &table[begin_row][0]);
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MPI_Gatherv(sendbuf, send_count, MPI_INT,
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&table[0][0], recv_counts, displs, MPI_INT, i, MPI_COMM_WORLD);
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}
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/* Everybody should have the same table now.
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*
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* The entries are:
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* Table[i][j] = (i/block_size) + 10;
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*/
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for (i = 0; i < MAX_PROCESSES; i++)
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if ((table[i][0] - table[i][MAX_PROCESSES - 1] != 0))
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errors++;
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for (i = 0; i < MAX_PROCESSES; i++) {
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for (j = 0; j < MAX_PROCESSES; j++) {
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if (table[i][j] != (i / block_size) + 10)
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errors++;
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}
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}
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if (errors) {
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/* Print out table if there are any errors */
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for (i = 0; i < MAX_PROCESSES; i++) {
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printf("\n");
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for (j = 0; j < MAX_PROCESSES; j++)
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printf(" %d", table[i][j]);
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}
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printf("\n");
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}
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}
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MTest_Finalize(errors);
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return MTestReturnValue(errors);
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}
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