using newton method

iter        root        err   err(est)

    1  3.0000000 +0.7639320 -2.0000000

    2  2.3333333 +0.0972654 -0.6666667

    3  2.2380952 +0.0020273 -0.0952381

Converged:

    4  2.2360689 +0.0000009 -0.0020263