#!/bin/sh

# grep -i would misbehave for any matched line containing a character

# (like "I" in the tr_TR.utf8 locale) whose lower-case representation

# occupies more bytes (two in this case, for 0xc4b1, aka U+0131).

# Copyright (C) 2011-2017 Free Software Foundation, Inc.

# This program is free software: you can redistribute it and/or modify

# it under the terms of the GNU General Public License as published by

# the Free Software Foundation, either version 3 of the License, or

# (at your option) any later version.

# This program is distributed in the hope that it will be useful,

# but WITHOUT ANY WARRANTY; without even the implied warranty of

# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the

# GNU General Public License for more details.

# You should have received a copy of the GNU General Public License

# along with this program.  If not, see <http://www.gnu.org/licenses/>.

. "${srcdir=.}/init.sh"; path_prepend_ ../src

require_tr_utf8_locale_

require_compiled_in_MB_support

# Before this change, grep could print a lot of uninitialized memory:

# $ printf "IIIIIII\n" > in

# $ for i in $(seq 10); do LC_ALL=tr_TR.utf8 src/grep -i . in|wc -c; done

# 760

# 754

# 585

# 298

# 273

# 458

# 660

# 552

# 936

# 678

fail=0

printf "IIIIIII\n" > in || framework_failure_

LC_ALL=tr_TR.utf8 grep -i .... in > out || fail=1

compare out in || fail=1

# Also exercise the case in which the original string and the lower-case

# buffer have precisely the same length (22 bytes here), yet internal

# offsets do differ.  Lengths are the same because while some bytes shrink

# when converted to lower case, others grow, and here they balance out.

i='I\304\260'

printf "$i$i$i$i$i$i$i\n" > in || framework_failure_

LC_ALL=tr_TR.utf8 grep -i .... in > out || fail=1

compare out in || fail=1

Exit $fail