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/*
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* ====================================================
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* Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
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*
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* Developed at SunPro, a Sun Microsystems, Inc. business.
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* Permission to use, copy, modify, and distribute this
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* software is freely granted, provided that this notice
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* is preserved.
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* ====================================================
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*/
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/*
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* scalbn (double x, int n)
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* scalbn(x,n) returns x* 2**n computed by exponent
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* manipulation rather than by actually performing an
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* exponentiation or a multiplication.
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*/
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#include <math.h>
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#include <math_private.h>
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static const double
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two54 = 1.80143985094819840000e+16, /* 0x43500000, 0x00000000 */
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twom54 = 5.55111512312578270212e-17, /* 0x3C900000, 0x00000000 */
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huge = 1.0e+300,
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tiny = 1.0e-300;
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double
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__scalbln (double x, long int n)
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{
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int64_t ix;
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int64_t k;
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EXTRACT_WORDS64(ix,x);
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k = (ix >> 52) & 0x7ff; /* extract exponent */
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if (__builtin_expect(k==0, 0)) { /* 0 or subnormal x */
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if ((ix & UINT64_C(0xfffffffffffff))==0) return x; /* +-0 */
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x *= two54;
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EXTRACT_WORDS64(ix,x);
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k = ((ix >> 52) & 0x7ff) - 54;
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}
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if (__builtin_expect(k==0x7ff, 0)) return x+x; /* NaN or Inf */
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if (__builtin_expect(n< -50000, 0))
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return tiny*__copysign(tiny,x); /*underflow*/
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if (__builtin_expect(n> 50000 || k+n > 0x7fe, 0))
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return huge*__copysign(huge,x); /* overflow */
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/* Now k and n are bounded we know that k = k+n does not
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overflow. */
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k = k+n;
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if (__builtin_expect(k > 0, 1)) /* normal result */
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{INSERT_WORDS64(x,(ix&UINT64_C(0x800fffffffffffff))|(k<<52));
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return x;}
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if (k <= -54)
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return tiny*__copysign(tiny,x); /*underflow*/
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k += 54; /* subnormal result */
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INSERT_WORDS64(x,(ix&INT64_C(0x800fffffffffffff))|(k<<52));
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return x*twom54;
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}
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#ifdef NO_LONG_DOUBLE
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strong_alias (__scalbln, __scalblnl)
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#endif
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